Mathjax CDN

When $a\ne 0$, there are two solutions to $a{x}^2+bx+c=0$ and they are $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\text{.}$$

When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$